5x^2+4x+47=0

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Solution for 5x^2+4x+47=0 equation:


Simplifying
5x2 + 4x + 47 = 0

Reorder the terms:
47 + 4x + 5x2 = 0

Solving
47 + 4x + 5x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
9.4 + 0.8x + x2 = 0

Move the constant term to the right:

Add '-9.4' to each side of the equation.
9.4 + 0.8x + -9.4 + x2 = 0 + -9.4

Reorder the terms:
9.4 + -9.4 + 0.8x + x2 = 0 + -9.4

Combine like terms: 9.4 + -9.4 = 0.0
0.0 + 0.8x + x2 = 0 + -9.4
0.8x + x2 = 0 + -9.4

Combine like terms: 0 + -9.4 = -9.4
0.8x + x2 = -9.4

The x term is 0.8x.  Take half its coefficient (0.4).
Square it (0.16) and add it to both sides.

Add '0.16' to each side of the equation.
0.8x + 0.16 + x2 = -9.4 + 0.16

Reorder the terms:
0.16 + 0.8x + x2 = -9.4 + 0.16

Combine like terms: -9.4 + 0.16 = -9.24
0.16 + 0.8x + x2 = -9.24

Factor a perfect square on the left side:
(x + 0.4)(x + 0.4) = -9.24

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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